2/3x^2+15=23

Solution for 2/3x^2+15=23 equation:

2/3x^2+15=23

We move all terms to the left:

2/3x^2+15-(23)=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x^2-8=0

We multiply all the terms by the denominator


-8*3x^2+2=0

Wy multiply elements

-24x^2+2=0

a = -24; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-24)·2
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*-24}=\frac{0-8\sqrt{3}}{-48}
=-\frac{8\sqrt{3}}{-48}
=-\frac{\sqrt{3}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*-24}=\frac{0+8\sqrt{3}}{-48}
=\frac{8\sqrt{3}}{-48}
=\frac{\sqrt{3}}{-6}
$